import concurrent.futures
import time
from pprint import pprint

start = time.perf_counter()

def power(n, desc1, desc2):
                                                                                                                    
    return f'{desc1} {n}^2 {desc2} = {n*n}'

Concurrent calculation with submit method. In this method the result are given when the thread is finished. It doesn’t wait the other threads to finish.

with concurrent.futures.ThreadPoolExecutor() as executor:
    numbers = [5, 4, 3, 2, 1, ]
    
    #You can use multiple parameters like number1, number2 or a string
    results = [executor.submit(power, number, 'Power of a Number', '*****') for number in numbers]
    
    for f in concurrent.futures.as_completed(results):
        print(f.result())

Power of a Number 4^2 ***** = 16
Power of a Number 5^2 ***** = 25
Power of a Number 1^2 ***** = 1
Power of a Number 3^2 ***** = 9
Power of a Number 2^2 ***** = 4

Concurrent with map method, it gives the results in the order they were started.

def power1(n, ):
                                                                                                                    
    return f'{n}^2 = {n*n}' 

with concurrent.futures.ThreadPoolExecutor() as executor:

    numbers = [5, 4, 3, 2, 1, ]
    results = executor.map(power1, numbers) 

    for result in results:
        print(result)


5^2 = 25
4^2 = 16
3^2 = 9
2^2 = 4
1^2 = 1

finish = time.perf_counter()

print(f'Finished in {round(finish-start, 2)} second(s)')

Finished in 19.03 second(s)